Meeting Rooms Ii Java

As soon as the current meeting is finished the room can be used for another.

Meeting rooms ii java.

Leetcode 253 meeting rooms ii. Meeting rooms ii given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei find the minimum number of conference rooms required for example. When we see the second meeting we check if its start time is later than the first meeting s end time.

Given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei determine if a person could attend all meetings. There are n meetings in the form of s i f i where s i is the start time of meeting i and f i is finish time of meeting i the task is to find the maximum number of meetings that can be accommodated in the meeting room. Suppose we have three meetings. For example given 0 30 5 10 15 20 return false.

It s not so we need another room. Meeting rooms easy. Meeting rooms ii given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei find the minimum number of conference rooms required. Facebook s 3rd most commonly asked question.

Given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei find the minimum number of conference rooms required. If you have a facebook interview this question is a must know. The next video is starting stop. Java solution when a room is taken the room can not be used for anther meeting until the current meeting is over.

We then compare the third meeting s start time with the minimum of first two meetings end times.